question_answer

In the reaction \[C{{H}_{3}}CN+C{{H}_{3}}MgI\to A\xrightarrow{{{H}_{2}}O/{{H}^{+}}}B\] The compound B is                          [KCET 1999]

A)                 Acetic acid          

B)                 Acetone

C)                 Acetaldehyde   

D)                 Ethyl alcohol

Correct Answer: B

Solution :

           \[C{{H}_{3}}CN+C{{H}_{3}}MgI\to \underset{\text{(A)}}{\mathop{{{(C{{H}_{3}})}_{2}}CNMgI}}\,\underset{-N{{H}_{3}}}{\mathop{\xrightarrow{{{H}_{2}}O/{{H}^{+}}}}}\,\]