A) Acetic acid
B) Benzaldehyde
C) Acetone
D) \[N{{H}_{3}}\]
Correct Answer: B
Solution :
Aniline reacts with benzaldehyde and forms Schiff's base (benzal aniline) or anils. \[{{C}_{6}}{{H}_{5}}-N{{H}_{2}}+O=CH{{C}_{6}}{{H}_{5}}\underset{-{{H}_{2}}O}{\mathop{\xrightarrow{\Delta }}}\,{{C}_{6}}{{H}_{5}}N=CH{{C}_{6}}{{H}_{5}}\] Benzylidine aniline
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