A) 5
B) 6
C) 3
D) 4
Correct Answer: D
Solution :
Because \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,H}}\,-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}\]has four methyl groups on the corner so it can produce for derivatives.
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