A) Both A and B are
B) Both A and B are
C) A is & B is
D) A is & B is
E) A is & B is
Correct Answer: C
Solution :
\[\xrightarrow{HBr}A\] Formation of A is a electrophilic addition reaction (i) \[HBr\to {{H}^{+}}+B{{r}^{-}}\] (ii) \[+{{H}^{+}}\to \overset{+}{\mathop{{{C}_{6}}{{H}_{5}}CHC{{H}_{3}}}}\,\] \[\underset{hv}{\mathop{\xrightarrow{HBr}}}\,\,B\] Formation of B is a free radical addition reaction (i) \[HBr\xrightarrow{hv}\overset{\bullet }{\mathop{H}}\,+\overset{\bullet \,\,\,}{\mathop{Br}}\,\] (ii) (iii)You need to login to perform this action.
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