A) 1
B) 2
C) \[\frac{\pi }{4}\]
D) 0
Correct Answer: D
Solution :
\[I=\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\cos \theta }d\theta =\int_{0}^{2\pi }{\frac{\sin (2\pi -2\theta )}{a-b\cos (2\pi -\theta )}d\theta }}\] Þ I \[=-\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\cos \theta }d\theta }\] \[\Rightarrow \,\,2I=0\Rightarrow \,\,\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\cos \theta }d\theta =0}\].
You need to login to perform this action.
You will be redirected in
3 sec
