A) 0
B) \[\int_{0}^{a}{\frac{1}{1+{{x}^{6}}}\ }dx\]
C) \[2\int_{0}^{a}{\frac{1}{1+{{x}^{3}}}\ }dx\]
D) \[\int_{0}^{a}{\frac{1}{1+{{(a-x)}^{3}}}\ }dx\]
Correct Answer: A
Solution :
Since \[\int_{-a}^{a}{f(x)}\ dx=0\],if \[f(-x)=-f(x)\] Therefore, \[\int_{-a}^{a}{\frac{dx}{x+{{x}^{3}}}}=0\].
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