A) 0
B) 4
C) 8
D) 1
Correct Answer: B
Solution :
\[\int_{0}^{\pi }{2\sin x\,dx+\int_{\pi }^{2\pi }{0.\,dx}}\]\[=2\,[-\cos x]_{0}^{\pi }+0\] \[=-2\,(\cos \pi -\cos 0)\]\[=-2\,(-1-1)=4\].
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