A) \[C{{H}_{3}}CN\]
B) \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
C) \[C{{H}_{3}}N{{H}_{2}}\]
D) None of the above
Correct Answer: C
Solution :
\[C{{H}_{3}}CON{{H}_{2}}\overset{NaOBr}{\mathop{\xrightarrow[\text{Hofmann}\,\text{bromamide}\,\text{reaction}]{}}}\,C{{H}_{3}}N{{H}_{2}}\]
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