A) Allyl alcohol
B) Formic acid
C) Glyceraldehyde
D) Glycerol monooxalate
Correct Answer: A
Solution :
\[\underset{\text{oxalic acid}}{\mathop{\underset{COOH}{\overset{COOH}{\mathop{|\ \ \ \ \ \ \ }}}\,\ }}\,+\ \underset{\text{Glycerol}}{\mathop{\underset{C{{H}_{2}}OH}{\overset{C{{H}_{2}}OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,HOH\ \,}}}\,}}\,\xrightarrow{380\ K}\ \underset{\text{Formic acid}}{\mathop{HCOOH}}\,\ +\ C{{O}_{2}}\uparrow \] \[\underset{\text{oxalic acid}}{\mathop{\underset{COOH}{\overset{COOH}{\mathop{|\ \ \ \ \ \ \ }}}\,\ }}\,+\ \underset{\text{Glycerol}}{\mathop{\underset{C{{H}_{2}}OH}{\overset{C{{H}_{2}}OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,HOH\ \,}}}\,}}\,\to \ \underset{\text{Dioxalin}}{\mathop{\underset{C{{H}_{2}}OH\ \,}{\overset{C{{H}_{2}}OCO}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,HO\ \overset{|}{\mathop{C}}\,O}}}\,}}\,\xrightarrow{-2C{{O}_{2}}}\underset{\text{Allyl alcohol}}{\mathop{\underset{C{{H}_{2}}OH}{\overset{C{{H}_{2}}\ \ \ \ }{\mathop{\underset{|}{\overset{||}{\mathop{C}}}\,H\ \ \ \ \ \ }}}\,}}\,\] Thus at 530 K allyl alcohol is formed.
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