question_answer

What amount of bromine will be required to convert 2 g of phenol into 2, 4, 6-tribromophenol [MP PET/PMT 1998]

A)                 4.00       

B)                 6.00

C)                 10.22    

D)                 20.44

Correct Answer: C

Solution :

                                1 mole   3 moles            1 mole            94 grams of phenol reacts with 480 gms. of \[B{{r}_{2}}\].                    2 gm. of phenol  ?  \[\frac{480}{94}\times 2=10.22\]gms.