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JEE Main & Advanced Physics Wave Mechanics Question Bank Progressive Waves

  • question_answer
    Equation of motion in the same direction are given by                    \[{{y}_{1}}=2a\sin (\omega t-kx)\] and \[{{y}_{2}}=2a\sin (\omega t-kx-\theta )\]            The amplitude of the medium particle will be [CPMT 2004]

    A)            \[2a\cos \theta \]              

    B)            \[\sqrt{2}a\cos \theta \]

    C)            \[4a\cos \theta /2\]          

    D)            \[\sqrt{2}a\cos \theta /2\]

    Correct Answer: C

    Solution :

                       Resultant amplitude \[{{A}_{R}}=2A\cos \,\left( \frac{\theta }{2} \right)=2\times (2a)\cos \,\left( \frac{\theta }{2} \right)=4a\cos \,\left( \frac{\theta }{2} \right)\]


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