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JEE Main & Advanced Physics Wave Mechanics Question Bank Progressive Waves

  • question_answer
    If the equation of transverse wave is  \[y=5\sin 2\pi \left[ \frac{t}{0.04}-\frac{x}{40} \right]\], where distance is in cm and time in second, then the wavelength of the wave is  [MH CET 2000; DPMT 2003]

    A)            60 cm                                      

    B)            40 cm

    C)            35 cm                                      

    D)            25 cm

    Correct Answer: B

    Solution :

     Comparing with \[y=a\sin 2\pi \left[ \frac{t}{T}-\frac{x}{\lambda } \right]\]Þ \[\lambda =40\]\[cm\]


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