A) \[\frac{\pi }{2}\]
B) \[\frac{2\pi }{3}\]
C) Zero
D) \[\frac{5\pi }{6}\]
Correct Answer: D
Solution :
Let the phase of second particle be \[\varphi \]. Hence phase difference between two particles is \[\Delta \varphi =\frac{2\pi }{\lambda }\Delta x\] Þ \[\left( \varphi -\frac{\pi }{3} \right)=\frac{2\pi }{60}\times 15\] \[\Rightarrow \varphi -\frac{\pi }{3}=\frac{\pi }{2}\Rightarrow \varphi =\frac{5\pi }{6}\]
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