question_answer

The area of the triangle formed by the line \[x\sin \alpha +y\cos \alpha =\sin 2\alpha \]and the coordinates axes is

A)            \[\sin 2\alpha \]                       

B)            \[\cos 2\alpha \]

C)            \[2\sin 2\alpha \]                     

D)            \[2\cos 2\alpha \]

Correct Answer: A

Solution :

           \[\Delta =\frac{1}{2}(2\sin \alpha .2\cos \alpha )=\sin 2\alpha \]