• # question_answer Two dice are thrown at a time. The probability that the difference of the numbers shown on the dice is 1 is ___. A)  $\frac{5}{18}$                     B)  $\frac{1}{36}$                     C)  $\frac{1}{6}$                       D)  $\frac{1}{18}$

Total number of outcomes = 36 Difference of numbers is 1, when pairs are (6, 5).(5, 4), (4, 3), (3, 2), (2, 1), (5, 6), (4, 5). (3, 4), (2, 3), (1, 2) $\therefore$    Total favourable outcomes =10 $\therefore$   Required probability $=\frac{10}{36}=\frac{5}{18}$