9th Class Mathematics Probability Question Bank Probability

  • question_answer
    A company selected 4000 households at random and surveyed them to find out a relationship between income level and the number of AC sets in their home. The information so obtained, is shown here.
    Monthly income (in Rs.) Number of
    AC/households
    0 1 2 Above 2
    <10000 20 80 10 0
    10000-14999 10 240 60 0
    15000-19999 0 380 120 30
    20000-24999 0 520 370 80
    25000 and above 0 1100 760 220
    Find the probability of households: (a) earning Rs. (15000-19999) per month and having more than one AC. (b) earning Rs. 25000 and more per month  and having exactly one AC. (c) not having any AC.

    A)                              
    (a) (b) (c)
    \[\frac{1}{8}\] \[\frac{11}{40}\] \[\frac{1}{200}\]

    B)
    (a) (b) (c)
    \[\frac{3}{80}\] \[\frac{17}{40}\] \[\frac{3}{400}\]

    C)
    (a) (b) (c)
    \[\frac{1}{8}\] \[\frac{17}{40}\] \[\frac{1}{200}\]

    D)
    (a) (b) (c)
    \[\frac{3}{80}\] \[\frac{11}{40}\] \[\frac{3}{400}\]

    Correct Answer: D

    Solution :

    Total number of households = 4000 Total number of possible outcomes = 4000 (a) Favourable outcomes = 120 + 30 = 150 Require probability (b) Favourable outcomes = 1100  Required probability (c) Number of households not having any A.C. have monthly income Rs. 10,000 and in the range Rs. Favourable outcomes = 20 +10 = 30  Required probability


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