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9th Class Mathematics Probability Question Bank Probability

  • question_answer
    What is the probability that a non-leap year contains 53 Saturdays?

    A) \[\frac{2}{7}\]                                   

    B)        \[\frac{1}{7}\]                   

    C)         \[\frac{2}{365}\]                                             

    D)         \[\frac{1}{365}\]             

    Correct Answer: B

    Solution :

    A non-leap year contains 365 days, i.e., 52 weeks + 1 day. \[S=\{S,M,T,W,Th,F,Sa\}\] \[\Rightarrow \]\[n(S)=7\] \[E=\{Saturday\}\] \[\Rightarrow \]\[n(E)=1\] \[\therefore \]\[P(E)=\frac{n(E)}{n(S)}=\frac{1}{7}\]


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