A) \[\frac{5}{18}\]
B) \[\frac{1}{36}\]
C) \[\frac{1}{6}\]
D) \[\frac{1}{18}\]
Correct Answer: A
Solution :
Total number of outcomes = 36 Difference of numbers is 1, when pairs are (6, 5).(5, 4), (4, 3), (3, 2), (2, 1), (5, 6), (4, 5). (3, 4), (2, 3), (1, 2) \[\therefore \] Total favourable outcomes =10 \[\therefore \] Required probability \[=\frac{10}{36}=\frac{5}{18}\]You need to login to perform this action.
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