• # question_answer Five cards-the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. If the queen is drawn and put aside, one card is then picked up at random, what is the probability that the second card picked up is (i) a king and (ii) a queen?                              A) (i) (ii) 1/4       0   B) (i) (ii) 1/2      0 C) (i) (ii) 1/13      0  D) (i) (ii) 1/3      ½

The queen is drawn and put aside, $\therefore$  Only 5-1=4 cards are left, $\Rightarrow$  Possible outcomes = 4 (i) $\because$  There is only one king $\therefore$  No. of favourable outcomes = 1             $\Rightarrow$            $P\,(an\,ace)=\frac{1}{4}$ (ii) Since, the only queen has already been put aside. $\therefore$   Number of possible outcomes =0 $\Rightarrow$  P (a queen) $=\frac{0}{4}=0$