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JEE Main & Advanced Physics Question Bank Prism Theory and Dispersion of Light

  • question_answer
    When light of wavelength \[\lambda \] is incident on an equilateral prism kept in its minimum deviation position, it is found that the angle of deviation equals the angle of the prism itself. The refractive index of the material of the prism for the wavelength \[\lambda \] is, then                                                              [Haryana CEE 1996]

    A)            \[\sqrt{3}\]                           

    B)            \[\frac{\sqrt{3}}{2}\]

    C)            2    

    D)            \[\sqrt{2}\]

    Correct Answer: A

    Solution :

               \[\mu =\frac{\sin \,\left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \frac{A}{2}}\] \[=\frac{\sin \,\left( \frac{60{}^\circ +60{}^\circ }{2} \right)}{\sin \,\left( \frac{60{}^\circ }{2} \right)}=\sqrt{3}\]


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