A) \[\sqrt{2}\]
B) \[\sqrt{3}\]
C) 1.5
D) 2.0
Correct Answer: A
Solution :
From figure it is clear that TIR takes place at surface AC and BC i.e. \[{{45}^{o}}>C\] \[\Rightarrow \sin {{45}^{o}}>\sin C\] \[\Rightarrow \frac{1}{\sqrt{2}}>\frac{1}{\mu }\]\[\Rightarrow \mu >\sqrt{2}\] Hence \[{{\mu }_{least}}=\sqrt{2}\]
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