JEE Main & Advanced Physics Question Bank Prism Theory and Dispersion of Light

  • question_answer
    The angle of a prism is 60° and its refractive index is \[\sqrt{2}\]. The angle of minimum deviation suffered by a ray of light in passing through it is                                              [MP PET 2003]

    A)            About 20°                              

    B)            30°

    C)            60°

    D)            45°

    Correct Answer: B

    Solution :

                       \[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{A}{2} \right)}\]\[\Rightarrow \sqrt{2}\mu =\frac{\sin \left( \frac{60+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{60}{2} \right)}\]                    \[\Rightarrow \sqrt{2}\times \sin 30=\sin \,\left( \frac{60+{{\delta }_{m}}}{2} \right)\Rightarrow \sin {{45}^{o}}\]            \[=\sin \,\left( \frac{60+{{\delta }_{m}}}{2} \right)\Rightarrow {{\delta }_{m}}={{30}^{o}}\]


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