A) \[\rho ={{\rho }_{0}}[1+\gamma \,d\theta ]\]
B) \[\rho ={{\rho }_{0}}[1-\gamma \,d\theta ]\]
C) \[\rho ={{\rho }_{0}}\gamma d\theta \]
D) \[\rho ={{\rho }_{0}}/\gamma d\theta \]
Correct Answer: B
Solution :
Since, with increase in temperature, volume of given body increases, while mass remains constant so that density will decrease. i.e. \[\frac{\rho }{{{\rho }_{0}}}=\frac{m/V}{m/{{V}_{0}}}=\frac{{{V}_{0}}}{V}=\frac{{{V}_{0}}}{{{V}_{0}}(1+r\Delta \theta )}=(1-\gamma \Delta \theta )\] \ \[\rho ={{\rho }_{0}}(1-\gamma \Delta \theta )\]
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