A) Half of the radius of the vessel
B) Radius of the vessel
C) One-fourth of the radius of the vessel
D) Three-fourth of the radius of the vessel
Correct Answer: B
Solution :
Pressure at the bottom = \[h\rho g\] and pressure on the vertical surface = \[\frac{1}{2}h\rho g\] Now, according to problem Force at the bottom = Force on the vertical surface Þ \[h\rho g\times \pi {{r}^{2}}=\frac{1}{2}h\rho g\times 2\pi rh\] Þ h = r
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