A) H
B) 2H
C) 7H
D) 8H
Correct Answer: C
Solution :
\[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\]Þ \[({{P}_{0}}+h+g)\times \frac{4}{3}\pi {{r}^{3}}\]=\[{{P}_{0}}\times \frac{4}{3}\pi {{(2r)}^{3}}\] Where, h = depth of lake Þ \[h\rho g=7{{P}_{0}}\]Þ \[h=7\times \frac{H\rho g}{\rho g}=7H.\]
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