A) Formaldehyde
B) Ethyl alcohol
C) Methyl cyanide
D) Methyl iodide
Correct Answer: C
Solution :
\[C{{H}_{3}}-C\equiv N+C{{\bar{H}}_{3}}M{{g}^{+}}Br\to C{{H}_{3}}-\underset{C{{H}_{3}}\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C=N}}\,-}}\,MgBr\] \[C{{H}_{3}}-CO-C{{H}_{3}}+N{{H}_{3}}+Mg<\begin{matrix} Br \\ OH \\ \end{matrix}\]You need to login to perform this action.
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