A) \[C{{H}_{3}}COOH\]
B) \[C{{H}_{3}}CO\overset{+}{\mathop{N}}\,{{H}_{3}}C{{l}^{-}}\]
C) \[C{{H}_{3}}N{{H}_{2}}\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: A
Solution :
Amide, on treating with \[HN{{O}_{2}},\] give acids. \[C{{H}_{3}}CON{{H}_{2}}\underset{(HN{{O}_{2}})}{\mathop{\xrightarrow{NaN{{O}_{2}}/HCl}}}\,\underset{acetic\,acid}{\mathop{C{{H}_{3}}COOH}}\,+{{N}_{2}}+{{H}_{2}}O\]
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