A) \[C{{H}_{3}}CHO\]
B) \[C{{O}_{2}}\]
C) \[{{(C{{H}_{3}})}_{2}}CO\]
D) \[HCHO\]
Correct Answer: B
Solution :
\[C{{O}_{2}}\] adds to Grignard?s reagent to yield acids. \[C{{O}_{2}}\xrightarrow{C{{H}_{3}}Mg\,I}C{{H}_{3}}COOMg\,I\xrightarrow{H.\ OH}C{{H}_{3}}COOH\]\[+Mg<\begin{matrix} OH \\ I \\ \end{matrix}\]You need to login to perform this action.
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