A) Ethyl formate
B) Ethyl chloroformate
C) Acetyl chloride
D) Carbon dioxide
Correct Answer: B
Solution :
\[C{{H}_{3}}MgI+\underset{\text{Ethyl}\,\text{chloroformate}}{\mathop{Cl-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O{{C}_{2}}{{H}_{5}}}}\,\to \]\[\left[ Cl-\,\underset{C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,}{\overset{OMgI\,\,\,\,\,\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\overset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C-O{{C}_{2}}{{H}_{5}}}}}\,}}}\, \right]\]\[\to \underset{\text{Ethyl}\,\text{acetate}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O{{C}_{2}}{{H}_{5}}}}\,+Mg<\begin{matrix} Br \\ I\,\,\, \\ \end{matrix}\]
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