A) \[{{N}_{2}}O\]
B) \[N{{H}_{3}}\]
C) \[C{{H}_{3}}N{{H}_{2}}\]
D) \[{{H}_{2}}NCON{{H}_{2}}\]
Correct Answer: D
Solution :
\[\underset{\begin{smallmatrix} \text{Ammonium} \\ \text{chloride} \end{smallmatrix}}{\mathop{2N{{H}_{4}}Cl}}\,+\underset{\begin{smallmatrix} \text{Potassium} \\ \text{Cyanate} \end{smallmatrix}}{\mathop{KCNO}}\,\to \underset{\text{Urea}}{\mathop{N{{H}_{2}}-CO-N{{H}_{2}}}}\,+KCl\]
You need to login to perform this action.
You will be redirected in
3 sec
