A) \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
B) \[C{{H}_{3}}CN\]
C) \[HCON{{H}_{2}}\]
D) \[C{{H}_{3}}CON{{H}_{2}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}Cl\underset{-KCl}{\mathop{\xrightarrow{KCN}}}\,C{{H}_{3}}CN\xrightarrow{{{H}_{2}}O}C{{H}_{3}}COOH\] \[\xrightarrow{N{{H}_{3}}}C{{H}_{3}}COON{{H}_{4}}\xrightarrow{\Delta }C{{H}_{3}}CON{{H}_{2}}\]
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