JEE Main & Advanced Chemistry Alcohols, Phenols and Ethers / एल्कोहॉल, फीनॉल तथा ईथर Question Bank Preparation of alcohol Phenol and Ethers

  • question_answer
    Action of water in the presence of sulphuric acid with the following alkenes (i)            \[C{{H}_{3}}-CH=C<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}\] and (ii)           \[C{{H}_{3}}-CH=C{{H}_{2}}\] gives

    A)                 \[C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,\ \ }}\,<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}\] and (ii) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}\]

    B)                 (i) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,H}}\,=CH<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}\] and(ii) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]

    C)                 (i) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,H}}\,-CH<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}\] and (ii) \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}\]

    D)                 (i) \[C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,\ \ }}\,<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}\] and(ii) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]

    Correct Answer: A

    Solution :

               \[\underset{\text{2 methyl 2 butene}}{\mathop{C{{H}_{3}}-CH=C<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}}}\,+{{H}_{2}}O\underset{\text{Markownikoff rule}}{\mathop{\xrightarrow{{{H}_{2}}S{{O}_{4}}}}}\,\]\[\underset{\text{2 methyl butan-2-ol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{OH\ }{\mathop{\underset{|}{\mathop{C}}\,\ \ \ \ }}\,<\begin{matrix}    C{{H}_{3}}  \\    C{{H}_{3}}  \\ \end{matrix}}}\,\]                                 \[\underset{\text{propene}}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,+{{H}_{2}}O\underset{\text{Markownikoff rule}}{\mathop{\xrightarrow{{{H}_{2}}S{{O}_{4}}}}}\,\underset{\text{propene-2-ol}}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,H}}\,-C{{H}_{3}}}}\,\]


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