question_answer

The compound that will react most readily with NaOH to form methanol is           [IIT-JEE (Screening) 2001]

A)                 \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}{{I}^{-}}\]              

B)                 \[C{{H}_{3}}OC{{H}_{3}}\]

C)                 \[{{(C{{H}_{3}})}_{3}}{{S}^{+}}{{I}^{-}}\]               

D)                 \[{{(C{{H}_{3}})}_{3}}Cl\]