A) \[{{C}_{2}}{{H}_{5}}C{{H}_{2}}CHO\]
B) \[{{C}_{2}}{{H}_{5}}C{{H}_{2}}C{{H}_{2}}OH\]
C) \[{{C}_{2}}{{H}_{5}}C{{H}_{2}}OH\]
D) \[{{C}_{2}}{{H}_{5}}CHO\]
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}MgBr+\underset{\overset{\,}{\mathop{\,\overset{\backslash /}{\mathop{O}}\,}}\,}{\mathop{{{H}_{2}}C-C{{H}_{2}}}}\,\xrightarrow{{{H}_{2}}O}\]\[\underset{n\text{-butyl}\,\text{alcohol}}{\mathop{\underset{(A)}{\mathop{{{C}_{2}}{{H}_{5}}C{{H}_{2}}C{{H}_{2}}OH}}\,}}\,+MgBr(OH)\]
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