question_answer

Arrange the steps of construction while constructing a quadrilateral ABCD given AB = 5.1 cm, AO = 4 cm, BC = 2.5 cm, \[\angle A=60{}^\circ \] and \[\angle B=85{}^\circ .\]

Step 1: With B as centre and radius 2.5 cm, cut off BC = 2.5 cm along BY.

Step 2 : Construct \[\angle XAB=60{}^\circ \] at A.

Step 3: Join\[CD\].

Step 4: With A as centre and radius 4cm, cut off AD =4 cm along AX.

Step 5: Draw \[\text{AB=5}\text{.1 cm}\].

Step 6: Construct \[\angle ABY=85{}^\circ \] at \[B\].

A)  5, 2, 4, 1, 3, 6

B)  5, 4, 2, 1. 6, 3

C)  5, 2, 4, 6, 1, 3

D)  5, 2, 4, 1, 6, 3