A) \[0\]
B) \[2/5\]
C) \[5/2\]
D) \[-1\]
Correct Answer: B
Solution :
Let \[p(x)=3{{x}^{3}}+8{{x}^{2}}+8x+3+5k\] \[\Rightarrow \]\[-2+5k=0\](Since, it is given tath\[{{x}^{2}}+x+1\]is a factor of\[3{{x}^{3}}+8{{x}^{2}}\]\[+\,8x+3+5k,\])the remainder is equal to 0) \[\Rightarrow \]\[k=\frac{2}{5}\]You need to login to perform this action.
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