A) \[p>r\]
B) \[p=r\]
C) \[p<r\]
D) Both (a) and (c)
Correct Answer: B
Solution :
if \[y-2\]is a factor of \[p{{y}^{2}}+5y+r,\] \[\Rightarrow \]\[4p+r+10=0\] ??(i) If \[y-\frac{1}{2}\]is a factor of \[p{{y}^{2}}+5y+r,\] \[\Rightarrow \]\[\frac{p}{4}+\frac{5}{2}+r=0\] By solving (i) and (ii), we get \[p=r=-2\]You need to login to perform this action.
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