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9th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    If \[\mathbf{x+y+z}=0\] then \[\mathbf{3}\left[ \frac{{{\mathbf{x}}^{\mathbf{2}}}}{\mathbf{yz}}\mathbf{+}\frac{{{\mathbf{y}}^{\mathbf{2}}}}{\mathbf{zx}}\mathbf{+}\frac{{{\mathbf{z}}^{\mathbf{2}}}}{\mathbf{xy}} \right]\mathbf{=?}\]

    A)  \[{{\left( xyz \right)}^{2}}\]                  

    B)  \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}\]

    C)  9 

    D)  3

    Correct Answer: C

    Solution :

    (c): \[3\left[ \frac{{{x}^{2}}}{yz}+\frac{{{y}^{2}}}{zx}+\frac{{{z}^{2}}}{xy} \right]=3\left[ \frac{{{x}^{3}}+{{y}^{3}}+{{z}^{3}}}{xyz} \right]\] \[=3\left[ \frac{3xyz}{xyz} \right]=9\]                             


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