A) \[x(1-2y)(1+2y+4{{y}^{2}})\]
B) \[x(1+2y)(1+2y+4{{y}^{2}})\]
C) \[x(1-2y)(1-2y+4{{y}^{2}})\]
D) \[x(1+2y)(1-2y+4{{y}^{2}})\]
Correct Answer: A
Solution :
\[x=8x{{y}^{3}}=x(1-8{{y}^{3}})=x[{{1}^{3}}-{{(2y)}^{3}}]\] \[=x(1-2y)(1+2y+4{{y}^{2}})\]
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