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9th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    If \[\mathbf{(x+2)}\] and \[\left( \mathbf{x+3} \right)\] are two factors of \[{{\mathbf{x}}^{\mathbf{3}}}+\mathbf{9}{{\mathbf{x}}^{\mathbf{2}}}+\mathbf{26x}+\mathbf{24},\]then the third factor is

    A)  \[x+7\]                        

    B)  \[x+9\]          

    C)  \[x+4\]      

    D)  \[~x+8\]

    Correct Answer: C

    Solution :

    (c): \[\frac{{{x}^{3}}+9{{x}^{2}}+26x+24}{(x+2)(x+3)}=\frac{(x+2)(x+3)(x+4)}{(x+2)(x+3)}=(x+4)\] \[\therefore \,\,\text{3rd}\,\text{factor}=(x+4)\]                


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