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9th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    If \[\mathbf{x}=\mathbf{999}\], then the value of \[\sqrt[\mathbf{3}]{\mathbf{x}\left( {{\mathbf{x}}^{\mathbf{2}}}\mathbf{+3x+3} \right)\mathbf{+1}}\]is

    A)  1000

    B)  999

    C)  998                             

    D)  1002

    Correct Answer: A

    Solution :

    (a): \[x=999\] Now, \[\sqrt[3]{x({{x}^{2}}+3x+3)+1}=\sqrt[3]{{{x}^{3}}+3{{x}^{2}}+3x+1}\] \[x=998\]         


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