A) \[33x-13y+32z+45=0\]
B) \[x-3y+z-5=0\]
C) \[33x+13y+32z+45=0\]
D) None of these
Correct Answer: D
Solution :
Equation of plane bisecting the angle containing origin is (making constant term of same sign) \[\frac{-3x+6y-2z-5}{\sqrt{{{3}^{2}}+{{6}^{2}}+{{2}^{2}}}}=+\left[ \frac{4x-12y+3z-3}{\sqrt{{{4}^{2}}+{{12}^{2}}+{{3}^{2}}}} \right]\] or \[\frac{-3x+6y-2z-5}{7}=\frac{4x-12y+3z-3}{13}\] or \[67x-162y+47z+44=0\].
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