JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Plane

  • question_answer
    The equation of the  perpendicular from the point  \[(\alpha ,\beta ,\gamma )\] to the plane \[ax+by+cz+d=0\]is [MP PET 2003]

    A)            \[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=0\]

    B)            \[\frac{x-\alpha }{a}=\frac{y-\beta }{b}=\frac{z-\gamma }{c}\]

    C)            \[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=abc\]

    D)            None of these

    Correct Answer: B

    Solution :

               It is a line passing through \[(\alpha ,\,\,\beta ,\,\,\gamma )\] and whose direction cosines are \[a,\,\,b,\,\,c.\]


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