A) 1 : 2
B) 2 : 1
C) 4 : 1
D) 1 : 4
Correct Answer: B
Solution :
Work function\[=\frac{hc}{{{\lambda }_{0}}}\]; where \[{{\lambda }_{0}}\] is threshold wavelength. \[\therefore \]\[\frac{{{W}_{{{0}_{1}}}}}{{{W}_{{{0}_{2}}}}}=\frac{{{\lambda }_{{{0}_{2}}}}}{{{\lambda }_{0}}_{1}}=\frac{2}{1}\]
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