A) Photographic plates are sensitive to infrared rays
B) Photographic plates are sensitive to ultraviolet rays
C) Infra-red rays are invisible but can cast shadows like visible light
D) Infrared photons have more energy than photons of visible light
Correct Answer: D
Solution :
\[E\propto \frac{1}{\lambda };\] also \[{{\lambda }_{\text{infrared}}}>{{\lambda }_{\text{visible}}}\] so \[{{E}_{\text{infrared}}}<{{E}_{\text{visible}}}\]
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