A) \[2\lambda \]
B) \[4\lambda \]
C) \[6\lambda \]
D) \[8\lambda \]
Correct Answer: B
Solution :
By using \[\frac{hc}{e}\left( \frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}} \right)={{V}_{0}}\] \[\Rightarrow \frac{hc}{e}\left( \frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}} \right)=4.8\] ?..(i) and \[\frac{hc}{e}\left( \frac{1}{2\lambda }-\frac{1}{{{\lambda }_{0}}} \right)=1.6\] ?..(ii) From equation (i) by (ii), \[\frac{\left( \frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}} \right)}{\left( \frac{1}{2\lambda }-\frac{1}{{{\lambda }_{0}}} \right)}=\frac{4.8}{1.6}\Rightarrow {{\lambda }_{0}}=4\lambda \].
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