A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{2}\]
C) \[\pi \]
D) \[2\pi \]
Correct Answer: A
Solution :
Period of \[|\sin 2x|\]. Period of \[\sin 2x=\frac{2\pi }{2}=\pi \] and period of \[|\sin 2x|=\frac{\pi }{2}\].
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