JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Periodic functions

  • question_answer
    The period of the function \[y=\sin 2x\]is  [Kerala (Engg.) 2002]

    A) \[2\pi \]

    B) \[\pi \]

    C) \[\pi /2\]

    D) \[4\pi \]

    Correct Answer: B

    Solution :

    Q Period of \[\sin (ax+b)=\frac{2\pi }{|a|}\] \ Period of \[\sin 2x=\frac{2\pi }{|2|}=\pi .\]


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