A) \[111\text{ }c{{m}^{2}}\]
B) \[100\text{ }c{{m}^{2}}\]
C) \[183\,c{{m}^{2}}\]
D) \[294\,\,c{{m}^{2}}\]
Correct Answer: C
Solution :
We have, \[AB=24.5\text{ }cm,\text{ }BC=12\text{ }cm\] \[\therefore \] Area of rectangle ABCD \[=24.5\times 12=294\text{ }c{{m}^{2}}\] Now, \[GH=[24.5-(3+3)]\,cm\] \[=(24.5-6)\,cm=18.5\,cm\] \[GF=[12-(3+3)]cm=(12-6)cm=6cm\] \[\therefore \] Area of rectangle EFGH \[=18.5\times 6=111\text{ }c{{m}^{2}}\] So. unshaded area \[=294-111=183\text{ }c{{m}^{2}}\]
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