A) 716 sq. cm
B) 784 sq. cm
C) 700 sq. cm
D) 768 sq. cm
Correct Answer: B
Solution :
: Area of square PQRS \[=(32\times 32)\,sq.\,cm\] \[=1024\text{ }sq.\text{ }cm\] Length of rectangle TUVW \[=(32-12)\,cm\] \[=20\text{ }cm\] Breadth of rectangle TUVW \[=(32-20)\,cm\] \[=12\text{ }cm\] So, area of rectangle TUVW \[=(12\times 20)\,sq.\,cm\] \[=240\text{ }sq.\text{ }cm\] \[\therefore \] Area of remaining figure \[=(1024-240)\,sq.\,cm=784\,sq.\,cm\]You need to login to perform this action.
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